Quiz 1 Results Page

### Explanation: 1. **Total number of ways to choose 2 cars out of 10:** \[ \binom{10}{2} = \frac{10!}{2!(10-2)!} = \frac{10 \times 9}{2 \times 1} = 45 \] 2. **Number of ways to choose 2 defective cars out of 3:** \[ \binom{3}{2} = \frac{3!}{2!(3-2)!} = \frac{3 \times 2}{2 \times 1} = 3 \] 3. **Probability that both cars are defective:** \[ P(\text{both cars are defective}) = \frac{\text{Number of ways to choose 2 defective cars}}{\text{Total number of ways to choose 2 cars}} = \frac{3}{45} = \frac{1}{15} \] ### Correct Answer: B. \(\frac{1}{15}\)